Math, asked by krishnaveni321, 1 year ago

Vinay bought a pizza and cut it into three pieces. when he weighted the first piece he found that it was 7g lighter than the second piece and 4g,heavier than the third piece. if the whole pizza weighed 300g .how much did each of the three pieces weigh?​

Answers

Answered by technis5521
36

let, the weight of first peice be = x

 

∵ the first peice is 7g lighter than second peice

 ∴ the second peice is 7g heavier than the first peice

 ∴ the weight of second peice = x+7

∵ the first piece is 4g heavier then the third peice

 ∴the third peice is 4g lighter than the first peice

∴the weight of third peice = x-4

∵total weight of pizza = 300g

∴weight of first peice + weight os second peice+  weight of third peice = 300g

x + (x+7) + (x-4) = 300

x + x  + 7 + x - 4 = 300

x + x + x + 7 - 4 = 300

3x + 3 = 300

3x = 300 - 3

3x = 297

x = 297/3

x = 99

weight of first peice = x

                = 99

weight of second peice = x + 7

                       = 99 + 7

                       = 106

weight of third peice = x - 4

                  = 99 - 4

                  = 95

Answered by sri420
0

Step-by-step explanation:

1st =x

2nd=x+7

3rd=x+4

1st Pizza slice +2nd Pizza slice+3rd Pizza slice is equals to 300 grams

=3 X + 3 = 300 grams

=3x. = 297

=x. =99

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