Vince went on a 3 day hiking trip. Each day, he walked 3/4 the distance that he walked the day before. He walked 83.25 kilometers total in the trip.
How far did Vince walk on the 1st day of the trip?
Answers
Answered by
1
Distance covered by Vince in 1st day is 36 km
Given that;
Total distance = 83.25 km
Number of days walking = 3
Find:
Distance cover by Vince in 1st day
Computation:
Assume;
Vince walked in 1st day = a
So,
a + (3/4)a + (3/4)(3/4)a = 83.25
a + (3/4)a + (9/16)a = 83.25
a + 0.75a + 0.5625a = 83.25
2.3125a = 83.25
a = 83.25 / 2.3125
a = 36
Distance cover by Vince in 1st day = 36 km
Given that;
Total distance = 83.25 km
Number of days walking = 3
Find:
Distance cover by Vince in 1st day
Computation:
Assume;
Vince walked in 1st day = a
So,
a + (3/4)a + (3/4)(3/4)a = 83.25
a + (3/4)a + (9/16)a = 83.25
a + 0.75a + 0.5625a = 83.25
2.3125a = 83.25
a = 83.25 / 2.3125
a = 36
Distance cover by Vince in 1st day = 36 km
Similar questions