Question

Vipin adds 3 litres of liquid A in 6 litres of liquid B and Mohit adds 8 litres of liquid A in 15 litres of liquidB. What is the ratio of the percentage of liquid B in the two mixtures?

Answer 1

in vipin's mixture => 6/9 *100 =66.66%
in mohit's mixture =>15/23*100 =65.21% (approx)
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Answer 2

The ratio of the percentage of liquid B in the two mixtures is 46:45.

Vipin adds 3L of liquid A in 6L of liquid B.

So, fraction of liquid B present = 6/(6+3) = 6/9

Percentage of liquid B present = (6/9) × 100% = 66.67%

Mohit adds 8L of liquid A in 15L of liquid B.

So, fraction of liquid B present = 15/(15+8) = 15/23

Percentage of liquid B present = (15/23) × 100% = 65.22%

So ratio of the percentages of milk in the two mixtures = (66.67%/65.22%) =

([6/9] / [15/23]) = 46/45

= 46 : 45

Required ratio = 46 : 45.