vivek gets rs 100 per days if he works but khe is finished by rs 10 per if he is absent in whole month of april he recived rs 1900only how many days did he work ? by arithmatic prograssion ?
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Answered by
1
Let x be the number of days he works.
and y be the number of days he absents.
he gets 100 Rs/day for working and 10Rs/day for absenting. in march he received 1900 Rs.
so, 100x - 10y = 1900
10x - y = 190 .......(1)
and x + y = 31 ........(2)
[ because number of days in march month is 31 ]
solve equations (1) and (2),
11x = 221 => x ≈ 20
and y = 10
so, he works 20 days and absents 10 days.
and y be the number of days he absents.
he gets 100 Rs/day for working and 10Rs/day for absenting. in march he received 1900 Rs.
so, 100x - 10y = 1900
10x - y = 190 .......(1)
and x + y = 31 ........(2)
[ because number of days in march month is 31 ]
solve equations (1) and (2),
11x = 221 => x ≈ 20
and y = 10
so, he works 20 days and absents 10 days.
Answered by
0
Given:
One day = 100 rupees
One day absent = 10 rupees
Amount = 1900 rupees
To find:
The number of working days.
Solution:
Framing an equation,
100 ( Working days ) - 10 ( Absent ) = 1900
10 ( working days ) - Absent = 190
Working days + Absent = 31
As march has 31 days.
Solving,
11 ( Working days ) = 221
Working days = 20.
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