Question

volume: 12ky²+8ky-20k. class -9 math page no.50 chapter 2 please give the pic of solution​

Answer 1

Explanation:

$12ky^2+8ky-20k$

$=4k(3y^2+2y-5)$

$=4k(3y^2-3y+5y-5)$

$=4k[3y(y-1)+5(y-1)]$

$=(4k)(y-1)(3y+5)$

From this, we can find many possibilities of the length and breadth. One such possibility is

$Length=(4k)(y-1)=4ky-4k\\Breadth=3y-5$

It all depends on what you want the dimensions to be.

Answer: Length = 4ky - 4k, Breadth = 3y-5

I hope this helps. :D

Answer 2

Answer:

here is your answer to your question