Question

Volume at NTP of oxygen required to completely
burn 1 kg of coal (100% carbon)
​

Answer 1

Answer:

V=1,866.66L

Explanation:

C+O2----->CO2

12g of C requires 22.4L of O2

1g will require=22.4/12

1kg(1000g) will require= 22.4*1000/12 L

22400/12L

=1,866.66L

Answer 2

Answer:

Mass of C = 1000 g

1 moles C requires 1 mole O₂    to burn.

Thus, 83.34 mole C requires 83.34 moles O₂  

At NTP, 1 mole gas occupies 22.4 litres.

83.34 moles occupies 83.34 × 22.4 = 1.86 × 10³  L

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Explanation: