Question

Volume occupied by 10g atom of oxygen at STP

Answer 1

ANSWER:

Points to remember:

We need to find the volume of 10g of oxygen atom at STP

We know that , any gas occupies 22.4L of volume at STP (Standrad temperature and pressure)

Here, we know that

When oxygen atom has a mass of 16g it occupies 22.4L of volume

Here, given oxygen atom = 10g

Solution:

Now,

At 16g of oxygen atom → 22.4 L of volume

At 10g of oxygen atom → ?

Let , ? be x

By cross multiplying we have

→ 16x = 22.4 × 10

→ x = 224 ÷ 16

→ x = 14 L

Hence , volume occupied by 10g of oxygen = 14L

Knowledge enhancer:

♦ Any gas occupies a volume of

22.4 L at STP

♦ STP : Standard temperature and pressure

• Standard temperature = 0°C → Convertion : 273 kelvins (K)
• Standard pressure = 1 atm → Convertion : 760 mm of Hg

Answer 2

TO FIND :–

• Volume occupied by 10g atom of oxygen at STP.

SOLUTION :–

▪︎ We know that –

=> Volume of occupied by a gas on STP = 22.4 L (For one mol gas )

• Let's calculate mol of oxygen –

=> Mol of oxygen = mass of substance / molecular mass

[ ∵ Molecular Mass of oxygen atom = 16 ]

=> Mol = 10/16

=> Mol = 5/8

• Volume of 1 mol gas = 22.4

• So that –

=> Volume occupied by gas = (22.4)(5/8)

=> Volume occupied by gas = (112/8)

=> Volume occupied by gas = 14 ltr.

• Hence , Volume occupied by 10g atom of oxygen is 14 litre.

• MORE ABOUT STP :–

(1) STP temperature = 298 k

(2) STP Pressure = 1 atm.

(3) STP Volume = 22.4 ltr.