volume occupied by hydrogen gas is 30.0ml at certain temperature and pressure. what volume would half this mass of hydrogen occupied at triple absolute temperature of the pressure where one ninth of original gas
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so
we know
PV=nRT
initial volume 30ml
P*30=nRT
P/9*V=n/2*R*3T
solve these two equations you should get 405ml
hope this right
we know
PV=nRT
initial volume 30ml
P*30=nRT
P/9*V=n/2*R*3T
solve these two equations you should get 405ml
hope this right
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