Volume occupied by one molecules of water (density =1 g cm -3) is.......
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Density of water is approximately 1g/ml
Thus 1g of water occupy volume = 1 ml
Molar mass of water = 18 g/mol
Number of moles of water in 1g = 118 moles = 0.055 moles H2O
Now 18 g water contain = 6.022×1023molecules H2O
Thus 1 g water will have = 6.022×102318 molecules H2O = 0.334 ×1023 molecules H2O
This shows that
0.334 ×1023 molecules H2O will occupy volume = 1 ml
Therefore volume occupied by 1 H2O molecule = 10.334×10−23 = 2.99 ×10-23 ml
Thus volume occupied by 1 H2O mlecule is 2.99 ×10-23 ml.
Thus 1g of water occupy volume = 1 ml
Molar mass of water = 18 g/mol
Number of moles of water in 1g = 118 moles = 0.055 moles H2O
Now 18 g water contain = 6.022×1023molecules H2O
Thus 1 g water will have = 6.022×102318 molecules H2O = 0.334 ×1023 molecules H2O
This shows that
0.334 ×1023 molecules H2O will occupy volume = 1 ml
Therefore volume occupied by 1 H2O molecule = 10.334×10−23 = 2.99 ×10-23 ml
Thus volume occupied by 1 H2O mlecule is 2.99 ×10-23 ml.
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