Volume occupied by the gas at stp of 30g of nitrogen(iv) oxide
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Explanation:
NO2 is the oxide with nitrogen in 4 oxidation state
mass given is 30
molarmass is 14+ 16*2 = 46
no of moless is mass/molarmass
is 30/46
0.652
1 mole occupies 22.414L
0.652 mole occupies xL
Crossmultiplying
x= 22.414 * 0.652
=14.61L
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