Question

Volume occupy by 16g of oxygen at ntp

Answer 1

Explanation:

32g = 22.4 l

16 g = 22.4 *16 /32

= 11.2 l

Answer 2

Answer:

Explanation:

This is stp answer

ANSWER

Total no. of moles of O

2

​

=16/32moles=0.5moles

Volume of 1mole of O

2

​

at STP=22.4L

so volume of 0.5mole=22.4*0.5=11.2L