Question

Volume of 1 g equivalent of H2 at NTP

Answer 1

Volume of 1 mole of H2 gas is 22.4 Litres at NTP
(1 mole of H2 gas is 2 grams ).So Volume of 1 gms of H2 gas at NTP =22.4/2=11.2 Litres.

Answer 2

Answer: The volume of given amount of $H_2$ at NTP is 11.2 L.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of hydrogen = 1 g

Molar mass of hydrogen = 2 g/mol

Putting values in above equation, we get:

$\text{Moles of }H_2=\frac{1g}{2g/mol}=0.5mol$

At NTP:

1 mole of a gas occupies 22.4 L of volume.

So, 0.5 moles of hydrogen gas will occupy = $\frac{22.4L}{1mol}\times 0.5mol=11.2L$ of volume.

Hence, the volume of given amount of $H_2$ at NTP is 11.2 L.