volume of a gas at 298k and 0.98bar is 250ml .what additional pressure is required to make the volume of gas 200ml at same temperature?
Answers
Answered by
5
Ideal Gas Equation : pv = nRT
Here , n,R and T are constant
So , p is inversely proportional to v
p(i)/p(f) = v(f) / v(i)
p(f) = 250/200 × 0.98 = 1.225 bar
Additional Pressure : 1.225 - 0.98 = 0.245 bar
Here , n,R and T are constant
So , p is inversely proportional to v
p(i)/p(f) = v(f) / v(i)
p(f) = 250/200 × 0.98 = 1.225 bar
Additional Pressure : 1.225 - 0.98 = 0.245 bar
Answered by
2
Let p be the additional pressure...
then,
pV/T = constant
pV = constant
0.98 × 250 = (0.98+p) × 200
200×p = 0.98 × 50
p = 49/200
p = 0.245 bars
then,
pV/T = constant
pV = constant
0.98 × 250 = (0.98+p) × 200
200×p = 0.98 × 50
p = 49/200
p = 0.245 bars
sonu323:
thanks yash
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