Volume of a solid regular hexagonal prism whose perimeter of base is 24 cm and height is 10 cm, is
Answers
Answer:
240√3cm^3
Step-by-step explanation:
area of base multiple with height = volume of prism
24√3×10= 240√3
Given,
The perimeter of the base of a solid regular hexagonal prism = 24 cm
Height of the hexagonal prism = 10 cm
To find,
We have to find the volume of the hexagonal prism.
Solution,
The volume of the solid regular hexagonal prism whose perimeter of the base is 24 cm and height is 10 cm, is 240√3 cm³.
It is given that the base of a solid regular hexagonal prism is 24 cm, which can be divided into 6 equilateral triangles,
Side of each equilateral triangle = 4 cm
Now, the area of the equilateral triangle = √3/4 * side²
Area of the base of the equilateral triangle = 6 * √3/4 * side²
= 6 * √3/4 * 16
= 24√3 cm²
Volume = Area of base * height
The volume of the solid regular hexagonal prism = 24√3 * 10
= 240√3 cm³
Hence, the volume of the solid regular hexagonal prism whose perimeter of the base is 24 cm and height is 10 cm, is 240√3 cm³.
