Question

Volume of certain quantity of gas at N.T.P. is 12 litres. What will be the pressure exerted by same quantity of gas when enclosed in a gas cylinder of 10 litres at 273degree celsius?​

Answer 1

Explanation:

PV=nRT

PV=nRT=

m

w

RT

1×V=

120

12

×R×(273+t) (i)

1.1×V=

120

12

×R×(273+t+10) (ii)

Dividing equation (ii) by equation (i), we get

1.1=

(273+t)

(273+t+10)

or t=−173

∘

C

Putting this value in equation (i), we get

1×V=

120

12

×0.0821×(273−173)

or V=0.821L

∴V=x×1000=0.821×1000=821