volume of Co2 at STP formed when hundred ml of 0.1 M H2 S o4 reacts with excess of N A 2 c o 3 is
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volume of Co2 at STP formed = 0.224 Liters or 224 ml
Explanation:
Given
volume of H2SO4 = 100 ml
molarity of H2SO4 = 0.1 M
volume of CO2 = ??
Solution
from chemical reaction
H2SO4 + Na2CO3 ---------> Na2SO4 + CO2 + H2O
As Na2CO3 is in excess,
thus, problrm is related to H2SO4
100 ml of 0.1 M H2SO4 = 100 x 0.1
100 ml of 0.1 M H2SO4 =10 mmole
1 mole (1000 mmole) of H2SO4 will liberate = 1 mole of CO2
1 mole of CO2 = 44 g or 22.4 Liter CO2
therefore
10 mmole H2SO4 liberate = 22.4 x 10/1000
10 mmole H2SO4 liberate = 0.224 Liters or 224 ml
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