Question

Volume of CO2 obtained at STP by complete decomposition of 9.85g Na2CO3​

Answer 1

Answer:

2.06 L

Explanation:

Na2CO3 → Na2O + CO2

1 mole of sodium carbonate give 1 mole of carbon dioxide.

as 105.98g sodium carbonate gives 44.01g carbon dioxide

therefore, 9.85 g sodium carbonate gives = 9.85 × 44.01 =4.09 g of CO2 105.98

Moles of CO2 mole = weight =4.09/44.01= 0.092 mole

Molar mass

1 mole of gas = 22.4 L gas

Therefore,0.092 mole of CO2 = 22.4 × 0.092 = 2.06 L CO2.

Answer 2

Answer:

answer is 2.02

hope it helps you