volume of co2 obtained at stp by the complete decomposition of 9.85
g of na2co3
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molar mass of Na2CO3=23*2+12+16*3=106 g
molar mass of CO2 = 44 g
106 g produces 44g
=> 9.85 g produces = 44*9.85/106
=4.08 g
molar mass of CO2 = 44 g
106 g produces 44g
=> 9.85 g produces = 44*9.85/106
=4.08 g
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