Question

volume of cone is 4620cm cube and hight is 10cm find the radious of its base

Answer 1

volume = 4620cm^2

height h = 10cm

volume of cone = πr^2h/ 3

πr^2h/ 3 = 4620

22(r)^2 × 10 /7× 3 = 4620

r^2 = 4620× 21/ 220

r^2 = 441 => r = √441

r = 21 cm

Answer: radius of its base = 21cm

Answer 2

Radius of base of cone is 21 cm.

Given:

• Volume of cone is 4620 cm³.
• Height (h) is 10 cm.

To find:

• Radius of base of cone.

Solution:

Formula to be used:

Volume of cone$\bf = \frac{1}{3} \pi \: {r}^{2} h \: {unit}^{3}$

Step 1:

Write all given values.

V= 4620 cm³

h=10 cm

Step 2:

Put the values in formula of volume.

$\frac{1}{3} \times \frac{22}{7} \times {r}^{2} \times 10 = 4620$

or

${r}^{2} = \frac{4620 \times 3 \times 7}{22 \times 10}$

or

cancel the common factors

${r}^{2} = 21 \times 21$

or

$\bf r = 21 \: cm$

Thus,

Radius of base of cone is 21 cm.

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