Question

Volume of nh3 gas obtained when 150 ml of h2 gas is treated with 100 ml of n2

Answer 1

Answer: 89.6 ml

Explanation: $N_2+3H_2\rightarrow 2NH_3$

According to avogadro's law, 1 mole of every gas occupy 22.4 Liters at STP

$\text{Number of moles}=\frac{\text{Given volume}}{\text{ Molar volume}}$

1) $\text{Number of moles of hydrogen}=\frac{150 ml}{22400 ml}=0.006$

2) $\text{Number of moles of nitrogen}=\frac{100 ml}{22400 ml}=0.004$

According to stochiometric coefficient in given balanced chemical equation:

3 moles of hydrogen reacts with 1 mole of nitrogen.

0.006 moles of hydrogen react=$\frac{1}{3}\times 0.006=0.002$ moles of nitrogen.

Thus hydrogen is the limiting reagent as it limits the formation of product and nitrogen is the excess reagent.

3 moles of hydrogen produce 2 moles of ammonia.

0.006 moles of hydrogen will produce=$\frac{2}{3}\times 0.006=0.004$ moles of ammonia

Volume of ammonia produced=${\text {number of moles}}\times {\text{Molar volume}}=0.004\times 22400 ml=89.6ml$

Answer 2

Answer:

100 ml

Explanation:

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