volume of oxygen required to complete combustion of 20 g of propane gas
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At STP, we have
1 mole = 22400cm^3 (22.4litres)
Of course all gases are affected by temperature or pressure and change quality.
But at STP we have for methane or ethylene for that matter.
50cm^3/22,400cm^3 = 1/448 moles.
= 0.002232142857143 moles.
Of course this value changes with temperature and pressure. Since you were asked for volume that doesn't matter. It doesn't matter because when you measure volumes of gases they all change together and the molar ratios don't change.
[Thank You]
1 mole = 22400cm^3 (22.4litres)
Of course all gases are affected by temperature or pressure and change quality.
But at STP we have for methane or ethylene for that matter.
50cm^3/22,400cm^3 = 1/448 moles.
= 0.002232142857143 moles.
Of course this value changes with temperature and pressure. Since you were asked for volume that doesn't matter. It doesn't matter because when you measure volumes of gases they all change together and the molar ratios don't change.
[Thank You]
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Answered by
1
CH3CH2CH3 + 5O2--------> 3CO2+4H2O
For 1 mole of propane 5 moles of oxygen is required
then for 20/44=2/5 moles of propane , 2 moles of oxygen is required
Hence , volume of oxygen required is 22.4L*2=44.8L
For 1 mole of propane 5 moles of oxygen is required
then for 20/44=2/5 moles of propane , 2 moles of oxygen is required
Hence , volume of oxygen required is 22.4L*2=44.8L
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