Question

volume of right circular come of height 9cm is 48πcm3, find the diameter of is base

Answer 1

Volume of cone=1/3πr^2h
=>1/3πr^2×9=48π
π r^2×3=48π
r^2×3=48
r^2=48/3
r^2=16
r=4
d=2r
d=2×4=8cm

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Answer 2

Answer:

Height of cone = 9cm

Let the radius be x

Volume = 48 π cm³

$\\ \implies \sf \: \frac{1}{3} \: \pi \: {r}^{2} \times 9 \: cm = 48 \: \pi \: {cm}^{3} \\ \\ \\ \implies \sf \: {x}^{2} = \sqrt{16} \\ \\ \\ \implies \sf \: x = 4 \:$

Diameter of base = 2x = 8 cm