Question

volumr of oxygen at NTP,required to completelyburn 1Kg of coal(100%carbon is?

Answer 1

C + O2 → CO2

we see , here ,
for burning of 12g Carbon , 22.4 L oxygen require

hence, for 1 g carbon , 22.4/12 L oxygen require .
hence, for 1 kg carbon 22.4× 1000/12 L
oxgen require .

so, volume of oxygen = 22400/12 L
= 1866.6667 L

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method 2 :-
no of mole of carbon = given wt /atomic wt = 1000/12
C + O2 → CO2
according to reaction
no of mole of C = no of mole of O2


volume of oxygen = no of mole of O2 × 22.4 L = 1000/12 × 22.4 L = 1866.6667 L