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Answered by
12
Answer:
given, y≥2x+1 and
y>
2
1
x−1
first, draw the graph for equations y=2x+1 and y=
2
1
x−1
for y=2x+1
substitute y=0 we get, 2x+1=0⟹x=−0.5
substitute x=0 we get, y=1
therefore, y=2x+1 line passes through (0.5,0) and (0,1) as shown in fig.
Hence, y≥2x+1 includes the region above the line.
for y=
2
1
x−1
substitute y=0 we get,
2
1
x−1=0⟹x=2
substitute x=0 we get, y=−1
therefore, y=2x+1 line passes through (2,0) and (0,-1) as shown in fig.
Hence, y>
2
1
x−1 includes the region above the line.
the intersection region is the shaded region as shown in above figure which includes I, II and III quadrants.
Therefore, quadrant IV has no solution
solution
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1
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