Question

VV
The energy of the excited state of
hydrogen atom us -0,85 ev. Find
the principle quantum number of
the orbit!if ground state energy of hydrogen atom is -13.6​

Answer 1

Answer:

U can use the formula

→   E= -13.6 / n^2 = -0.85

→   n^2 = 13.6/0.85 = 16

→    thus n=4

Thanks!

Explanation: