Question

W If min.(2x? - ax + 2) > max.(b-1+2x– x?), a,be R then roots of the equation 2x + ax +(2-5) = 0
are
(A) positive and distinct
(B) negative and distinct
(C) opposite in sign
(D) imaginary​

Answer 1

Answer:

Step-by-step explanation:

f(x) =2x² -ax + 2

f'(x)  = 4x - a

4x - a = 0

=> x = a/4

f''(x) = 4

f''(x)  is + ve

=> x = a/4 will give minima of f(x)

f(a/4)  = 2a²/16  - a²/4 + 2

= a²/8  - a²/4  + 2

= 2 - a²/8

g(x) = b -1 + 2x - x²

g'(x)  = 2 - 2x

2 - 2x = 0

=> x = 1

g''(x) = -2

=> x =1 will give max value

g(1) = b - 1 + 2 - 1 = b

Now 2 - a²/8  >  b

further this equation 2x + ax +(2-5) = 0  does not look correct to solve further

Answer 2

Answer:

sorry guys this is spamming only

moderators delete after amitnrw sawed this

Step-by-step explanation:

coz i need help pls inbox me amitnrw ....

ur ans to one of my question is awesome

ur the brainly mathematecian