Question

Walking 5/6th of her usual speed, a woman is 18 minutes too late. The usual time taken by her to cover that distance is:

Answer 1

d=v*t. (1)

d=5/6*v *(t+18). (2)

v*t=5/6*v*(t+18)

t=5/6*(t+18)

6t=5t+90

t=90min

Solve two equations