Walking at 3/4 of his normal speed, mike is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and his office is
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Step-by-step explanation:
let originl speed is x
3/4 speed of norml speed is 3x/4
let distance b/w house and office =y
time taken on original speed =y/x
time taken when speed is 3/4th =y/3x/4
4y /3x -y/x= 16
4xy -3xy /3x=16
xy/3x=16
y/3=16
y =48
4x/3y =16
4x/144=16
x =144Γ4
x= 576km
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