walking at 3/4 of the speed, a man is late by 2and half hour. find his usual time .
plz solve it
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let suppose the man is travel x km dist.
in time t with speed u
then u = x/t .... eqn1
tthen when its speed 3u/4
3u/4 = x/90 ...... eqn2
( 2 and half hour = 90 mint )
then u = 4x/270
put it u value on eqn1
u get t= 270/4 mint..
in time t with speed u
then u = x/t .... eqn1
tthen when its speed 3u/4
3u/4 = x/90 ...... eqn2
( 2 and half hour = 90 mint )
then u = 4x/270
put it u value on eqn1
u get t= 270/4 mint..
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