Question

want a well explanation answer of question​

Answer 1

Answer

• The letters are chosen with replacement. So each time there are 6 letters to choose from.

• The word bad/ cad can be formed if the three letters in that word are picked in the three picks.

Probability of choosing ' c' or 'b' = 2/6 = 1/3.

Probability of choosing 'a' = 1/6

Probability of choosing ' b' = 1/6

These three picking events are independent.

• The order of getting them doesn't matter. So 3 ! = 6 permutations are possible.

Overall probability = 6 × 1/3 × 1/6 × 1/6

= 1/18.

Answer 2

Answer:

$the \: probability \: \\ of \: word \: cad \: and \: bad \: be \: \\ \\ = 4 \div 6 \\ = 2 \div 3$