Question

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a+b+c=9, ab+bc+ca=40
Find a square + b square +c square

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Answer 1

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★ SOLUTION

→ Given, a + b + c = 9 and ab + bc + ca = 40

We know that,

(a + b + c)2 = a² + b² + c² + 2ab + 2bc + 2ca

⇒ a²+ b² + c² = (a + b + c)² – 2 (ab + bc + ca)

⇒ a ² + b ² + c ² = (9)² – 2 × 40 = 81 – 80 = 1 [a + b + c = 9 and ab + bc + ca = 40]

Thus, the value of a² + b² + c² is 1 .

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Answer 2

Answer:

Step-by-step explanation:

Given, a + b + c = 9 and ab + bc + ca = 40

We know that,

(a + b + c)2 = a 2 + b 2 + c 2 + 2ab + 2bc + 2ca

⇒ a 2 + b 2 + c 2 = (a + b + c)2 – 2 (ab + bc + ca)

⇒ a 2 + b 2 + c 2 = (9)2 – 2 × 40 = 81 – 80 = 1 [a + b + c = 9 and ab + bc + ca = 40]

Thus, the value of a 2 + b 2 + c2 is 1 .

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