Question

WAP to accept n numbers in an array and display all the unique

numbers present in it using the following method.

boolean checkUnique(int x) To check if x is a unique number or not
A number is a unique number that starts and ends with the same digit
pls write this program in java(bluej)​

Answer 1

Answer:

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Print All Distinct Elements of a given integer array

Last Updated: 30-10-2020

Approach:

1. Put all input integers to hashmap’s key

2. Print keySet outside the loop

Java

import java.util.HashMap;

public class UniqueInArray2 {

public static void main(String args[])

{

int ar[] = { 10, 5, 3, 4, 3, 5, 6 };

HashMap<Integer,Integer> hm = new HashMap<Integer,Integer>();

for (int i = 0; i < ar.length; i++) {

hm.put(ar[i], i);

}

// Using hm.keySet() to print output reduces time complexity. - Lokesh

System.out.println(hm.keySet());

}

}

C#

Given an integer array, print all distinct elements in array. The given array may contain duplicates and the output should print every element only once. The given array is not sorted.

Examples:

Input: arr[] = {12, 10, 9, 45, 2, 10, 10, 45}

Output: 12, 10, 9, 45, 2

Input: arr[] = {1, 2, 3, 4, 5}

Output: 1, 2, 3, 4, 5

Input: arr[] = {1, 1, 1, 1, 1}

Output: 1