Computer Science, asked by nishantchoudhurybrol, 9 months ago

wap to input 35.6 and find the sum , product and average.

Answers

Answered by ıtʑFᴇᴇʟɓᴇãᴛ
12

\mathtt{\huge{\underline{\pink{Answer :-}}}}

Sum :-

\mathfrak{\large{\bf{\underline{\red{Programme :-}}}}}

int main() {

int n, i, sum = 0;

printf("18.6:17.2 ");

scanf("%d", &n);

i = 1;

while (i <= n) {

sum += i;

++i;

}

printf("Sum = %d", sum);

return 0;

}

\mathfrak{\large{\bf{\underline{\green{Output :-}}}}}

✒ 18.6 +17.4 = 35.8

__________________________________

Product :-

\mathfrak{\large{\bf{\underline{\red{Programme :-}}}}}

{

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.print("Input first number 17.9 : ");

int num1 = in.nextInt();

System.out.print("2: ");

int num2 = in.nextInt();

System.out.println(17.9 + " x " + 2 + " = " + num1 * num2);

}

\mathfrak{\large{\bf{\underline{\green{Output :-}}}}}

  • Input first number: 25

  • Input second number: 5

  • 25 x 5 = 125

__________________________________

Average :-

➝ 35.6 × 2 = 71.2

  • number 1 = 35.1

  • number 1 = 35.1number 2 = 36.1

\mathfrak{\large{\bf{\underline{\red{Programme :-}}}}}

int main()

{

int num1, num2;

float avg;

printf("35.1: ");

scanf("%d",&num1);

printf("36.1: ");

scanf("%d",&num2);

avg= (float)(35.1+36.1)/2;

//%.2f is used for displaying output upto two decimal places

printf("Average of %d and %d is: %.2f",35.1,36.1,avg);

return 0;

}

\mathfrak{\bf{\large{\underline{\green{Output :-}}}}}

  • First number: 35.1

  • Second number: 36.1

  • Average of 9 and 10 is: 35.6

__________________________________

Answered by Anonymous
5

Java code

import java.util.Scanner;

public class Exercise9 {

public static void main(String[] args)

{

Scanner in = new Scanner(System.in);

System.out.print("Input 1st integer: ");

int firstInt = in.nextInt();

System.out.print("Input 2nd integer: ");

int secondInt = in.nextInt();

System.out.printf("Sum of two integers: %d%n", firstInt + secondInt);

System.out.printf("Difference of two integers: %d%n", firstInt - secondInt);

System.out.printf("Product of two integers: %d%n", firstInt * secondInt);

System.out.printf("Average of two integers: %.2f%n", (double) (firstInt + secondInt) / 2);

System.out.printf("Distance of two integers: %d%n", Math.abs(firstInt - secondInt));

System.out.printf("Max integer: %d%n", Math.max(firstInt, secondInt));

System.out.printf("Min integer: %d%n", Math.min(firstInt, secondInt));

}

Input the 10 numbers :

Number-1 :1

Number-2 :2

Number-3 :3

Number-4 :4

Number-5 :5

Number-6 :6

Number-7 :7

Number-8 :8

Number-9 :9

Number-10 :10

The sum of 10 no is : 55

The Average is : 5.500000

hope this will help you

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