Question

WAP to input a number find 4 digit or not. if 4 digit number then find the number if AABB formed or not ex:5588, 2255.​

Answer 1

Let's understand the question..

• We need to accept 4-digit number from the user
• Then we have to check if the number forms AABB or not

But, How to check if the number is AABB or not?

>> Simple, Just break the number into two equal halves... and check if in each half the digits are same or not..

This logic can be well understood by an example..

• Let's say the number is 2233
• Divide this number into two equal halves... 22 33
• Now we will see if the digit of the first half is same or not.. 22 here the first and last digit is same.
• Same in the second half
• If condition comes true in both the half.. The number forms AABB

Now here comes the programming...

package Programmer;

import java.util.*;

public class Number {

public static void main (String ar [])

{

Scanner sc=new Scanner(System.in);

int n=sc.nextInt(); //Accepting input from the user

int D1=n/100;

int D2=n%100;

if((D1%10==D1/10)&&(D2%10==D2/10))

System.out.println("Number forms AABB");

}

}

•Output attached