Question

watching from the top of 340m high hill the angle of depression of the two houses situated in east and west of the hill are found to be 30*and 60* find the distance between two houses ​

Answer 1

Answer:

1.365km

Step-by-step explanation:

Let the distance between the nearer kilometre stone and the hill be 'x' km. 

So, the distance between the farther kilometre stone and the hill is '1+x' km since both are on the same side of the hill.

In triangle APB,

 tan450=xh

       ⇒1=xh

       ⇒h=x

In triangle AQB,

 tan300=1+xh

 ⇒31=1+xh

⇒1+x=3h

From equation 1,

1+h=3h⇒1=3h−h

⇒h=3−11 

⇒h=1.365km

Hope this help you.