Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v1 and v2 respectively.
(a) v1 = v2
(b) v1 = 13.6 v2
(c) v1 = v2/13.6
(d) v1=√13.6 v2
Answers
Answered by
0
Answer:
Since velocity of liquid coming out of tank is irrespective of density of material & given as velocity = \sqrt { 2gh }2gh. Hence both will come out at same velocity.
Answered by
0
(a) v1 = v2
Explanation:
- The efflux velocity (the velocity of the fluid comes out from the hole) v = √(2gh).
- From the above formula, it clearly shows that the velocity is dependent of only gravitational field strength and height of the filled liquid (which are same for both the liquids in the above problem) and completely independent of density.
- So, the velocity of water (V1) and mercury (V2) coming out of the holes are equal.
Similar questions