Water drops fall at regular intervals fro a tap which is 5 m above ground.The third drop is leaving
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1
Answer:
Given:
Height =h=5m
To calculate time taken by first drop to reach ground:
u=0m/s, t=T
so,
s=ut+1/2at²
5=0+1/2aT²-----(1)
Time taken by second drop will be T/2
Therefore, its distance from tap
h=0+1/2(aT²)/4 ------------(2)
divide equ (ii) by equ (1)
h/5=1/4
h=1.25m
therefore H-h=5-1.25=3.75m
Option E is the correct answer.
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