water drops fall at regular intervals from. a tap 5m above the ground the third drop is leaving the tap the instant the first drop touches the ground how far the ground is the second day drop at that instanr
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Height of tap = 5m and (g) = 10 m/sec2.
For the first drop, 5 = ut + gt 2
= (0 × t) + × 10 t2 v= 5t2 or t2 = 1 or t = 1.
It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.
Distance covered by the second drop in 0.5 sec
= (0.5)2 = 1.25m
Therefore, distance of the second drop above the ground
= 5 - 1.25 = 3.75 m.
For the first drop, 5 = ut + gt 2
= (0 × t) + × 10 t2 v= 5t2 or t2 = 1 or t = 1.
It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.
Distance covered by the second drop in 0.5 sec
= (0.5)2 = 1.25m
Therefore, distance of the second drop above the ground
= 5 - 1.25 = 3.75 m.
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