Question

Water drops fall at regular intervals from a tap 6 m
above the ground. The third drop is leaving the tap
at the instant the first drop touches the ground. How
far above the ground is the second drop at that
instant?
(1) 1.25 m (2) 2.50 m (3) 3.75 m
(3) 3.75 m (4) 4.5 m​

Answer 1

Answer:

c)

Explanation:

Height of tap = 5m and (g) = 10m/sec

2

For the first drop, 5=ut+gt

2

=(0×t)+×10t

2v

=5t

2

or t

2

=1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)

2

=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m