Question

Water drops fall from a tap on to the floor 5.0m below at regular intervals of time. The height at which the third drop will be from ground, at the instant when the first drop strikes the ground is??

Answer 1

Explanation:

S=ut+1/2at^2 S1=ut+1/2×10t^2 =5t^2(u=0). S2=5(2t)^2=20t^2. S2=4S1 S1=5/4m from tap. From ground : 5-5/4=15/4m