Water enters through end A with a speed v₁ and leaves through end B with a speed v₂ of a cylindrical tube AB. The tube is always completely filled with water. In case I the tube is horizontal, in case II it is vertical with the end A upward and in Case III it is vertical with end B upward. We have v₁ = v₂ for
(a) Case I
(b) Case II
(c) Case III
(d) Each case.
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Case I ⇒ Since, the tube is of cylindrical shape, hence, area of cross-section is same. Now, Volume rate of flow is always constant.
Thus, applying equation of continuity,
a₁ × v₁ = a₂ × v₂
v₁ = v₂ [Since, a₁ = a₂].
Case II ⇒ In this case also, Equation of continuity will be valid. Hence, v₁ = v₂. [Whether A is at the top or B, both are having same cross-section, thus it does not make an sense.]
Case III ⇒ In this case also, Equation of continuity will be valid. Hence, v₁ = v₂.
''Hence, Correct answer is option (d). Each case.''
Hope it helps.
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