water flow out through a circular pipe whose internal daiameter is 2cm at rate of 7 meterper second into a cylindrical tank having radius of base 40cm. By how much will the level of water rise in half an hour
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Height of pipe = 7m = 700cm
Diameter of pipe = 2cm
Radius of pipe = 1cm
Volume of pipe = πr²h
= 22/7×1×1×700 = 22×100 = 2200cm³
Amount of water supplied by pipe in 1 sec = 2200cm³.
30min = 30×60 = 1800 Sec
The level of water will be rise in 30 Min ( 1800 sec) = 2200× 1800 = 3960000Cm³
Diameter of pipe = 2cm
Radius of pipe = 1cm
Volume of pipe = πr²h
= 22/7×1×1×700 = 22×100 = 2200cm³
Amount of water supplied by pipe in 1 sec = 2200cm³.
30min = 30×60 = 1800 Sec
The level of water will be rise in 30 Min ( 1800 sec) = 2200× 1800 = 3960000Cm³
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