Math, asked by vedansh17, 1 year ago

water flow out through a circular pipe whose internal daiameter is 2cm at rate of 7 meterper second into a cylindrical tank having radius of base 40cm. By how much will the level of water rise in half an hour

Answers

Answered by Panzer786
1
Height of pipe = 7m = 700cm

Diameter of pipe = 2cm

Radius of pipe = 1cm

Volume of pipe = πr²h

= 22/7×1×1×700 = 22×100 = 2200cm³

Amount of water supplied by pipe in 1 sec = 2200cm³.

30min = 30×60 = 1800 Sec

The level of water will be rise in 30 Min ( 1800 sec) = 2200× 1800 = 3960000Cm³



Answered by ashi1417
0
Hi dear here is your answer.
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