water flow through a horizontal pipe of radius 1cm at a speed of 2 ms^-2.what should be the diameter of its nozzle if the water is to come out at a speed of 10ms^-2
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SOLUTION::
Apply principle of continuity.
ρA₁V₁ = ρA₂V₂
=> A₁V₁ = A₂V₂
=> (π/4) × D₁² × V₁ = (π/4) × D₂² × V₂
=> D₁² × V₁ = D₂² × V₂
=> D₂² × V₂ = D₁² × V₁
=> D₂² × 4 = 2 × 2 × 1
∴ D₂ = 1 cm
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