Question

water flows out through a circular pipe whose internal radius is 1cm at rate of 80cm/second into an empty cylindrical tank, the radius of whose base is 40 cm. by how much will the level of water rise in the tank in half an hour

Answer 1

here is your solution , please mark best , sorry for the mistake but multiply the last answer by 100 , as I forgot to multiply 144π by 100, the final answer will be 9cm

Answer 2

Solution:

Given, radius of tank, r1 = 40 cm

Let height of water level in tank in half an hour = 1 cm.

Also, given internal radius of cylindrical pipe, r2 = 1 cm

and speed of water = 80 cm/s i.e., in 1 water flow = 80 cm

In 30 (min) water flow = 80x 60 x 30 = 144000 cm According to the question,

Hence, the level of water in cylindrical tank rises 90 cm in half an hour.