water flows out through a circular pipe whose internal diameter is 2cm at the rate of 6m/sec. into a cylindrical tank . if radius of base of the tank is 60cm . how much will the level of the water rise in half an hour?
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ANSWER:
METHOD:1
Internal Diameter = 2 cm , Internal Radius = 1 cm
Rate = 6 m / s , this implies 6 m in 1 sec
In 30 minutes = 30 * 60 = 1800 sec
6 m in 1 sec
10800 m in 1800 sec
Volume of cylindrical tank = pie * r * r * h = pie * 60 * 60 * h
Volume of circular pie = Volume of cylinder
pie * 1 * 1 * 10800 = pie * 60 * 60 * h
10800 / 60 * 60 = h
10800 / 3600 = h
h =3 cm
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METHOD:1
Internal Diameter = 2 cm , Internal Radius = 1 cm
Rate = 6 m / s , this implies 6 m in 1 sec
In 30 minutes = 30 * 60 = 1800 sec
6 m in 1 sec
10800 m in 1800 sec
Volume of cylindrical tank = pie * r * r * h = pie * 60 * 60 * h
Volume of circular pie = Volume of cylinder
pie * 1 * 1 * 10800 = pie * 60 * 60 * h
10800 / 60 * 60 = h
10800 / 3600 = h
h =3 cm
plz mark as brainliest
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