water flows out through a circular pipe whose internal radius is 1 cm at the rate of 80 cm per second into an Empty cylindrical tank the radius of whose base is 40 cm by how much will the level of water rise in the tank in half an hour
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half an hour = 30 minutes = 30*60 sec.
volume of water in 1 sec = πr²h = π * 1² * 80
volume of water in 30*60 sec. = π * 1² * 80 * 30 * 60 = π*144 = 144π cm³
So, the water is filled in water tank in half an hour is 144πcm³
base of tank is 40cm
area of tank is 40 * 40 = 1600cm²
volume of tank in which water is filled = area * height
area * height = 144π
1600 * h = 144π
h = 144π/1600 = 0.2828cm
hence, the level of water rise in the tank = 0.2828cm
volume of water in 1 sec = πr²h = π * 1² * 80
volume of water in 30*60 sec. = π * 1² * 80 * 30 * 60 = π*144 = 144π cm³
So, the water is filled in water tank in half an hour is 144πcm³
base of tank is 40cm
area of tank is 40 * 40 = 1600cm²
volume of tank in which water is filled = area * height
area * height = 144π
1600 * h = 144π
h = 144π/1600 = 0.2828cm
hence, the level of water rise in the tank = 0.2828cm
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