Question

Water flows out through a cylindrical pipe whose diameter is 2 cm at the rate of 7m/sec into a cylindrical tank of radius 40 cm. By how much will the level of water rise in 30 minutes?

Answer 1

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Answer 2

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Given diameter of the circular pipe = 2 cm

So, the radius of the circular pipe = 2/2 = 1 cm

Height of the circular pipe = 0.7 m = 0.7*100 = 70 cm

Now, volume of the water flows in 1 second = πr2 h

                                                           = 3.142*12 *70

                                                           = 3.142 * 70

Volume of the water flows in 1/2 hours =  3.142 * 70*30*60

Now, volume of the water flows = Volume of the cylinder

=> 3.142 * 70*30*60 = πr2 h

=> 3.142 * 70*30*60 = 3.142*(40)2 h

=> 70*30*60 = 40*40* h

=> h = (70*30*60)/(40*40)

=> h = (70*3*6)/(4*4)

=> h = 1260/16

=> h = 78.85 cm

So, the level of water rise in the tank in half an hour is 78.75 cm

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