Math, asked by aswany9738, 11 months ago

Water flows through a cylindrical pipe at a speed of 8 cm/s. The radius of the circular cross-section is 1.5 cm and the pipe is always completely full of water. Calculate the amount of water that flows through the pipe in 1 hour. Give your answer in litres.

Answers

Answered by wasif6793
18

area of crss section=pie ×r^2

=3.14× 1.5

=4.17

vol. of cyl. = 4.17×8

=37.68

in 1 sec. 37.68 ml water is came out from pipe

then in 1 hour= 60×60×37.68

=5135648 ml

in letre, 5135.648 l Ans.

please mark the answer as brainliest.

Answered by manaalmurtaza
4

Answer:

203.5 litres (1 d.p)

Step-by-step explanation:

8cm/s --> 8cm per second

1 hr = 3600 s

8 x 3600 = 28800 cm = length

V= \pi r^{2}

V= 3.14 * (1.5)^{2}  *28800 = 203472 cm^{2}

1 litre = dm^{3}

1 litre = 1000 cm^{2}

203472 / 1000 = 203.472 litres

ANSWER - 203.5 litres (1 d.p)

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