Question

water flows through a turbine in which friction causes the water temperature to rise from 35℃ to 37℃.if there is no heat transfer how much does the entropy of water change in passing through the turbine?

Answer 1

Answer:

The change in entropy is 27.18 J/k.

Explanation:

The specific heat of water is KJ/Kg.K.

ΔS=C(p)* ㏑[(T(2) / T(1)] →→→→→ equation 1

ΔS represents change in entropy.

C(p) represents specific heat of water.

T(2) and T(1) represents final and initial temperatures of water in kelvin.

T(1)= 273+35=308 K.

T(2)= 273+37= 310 K.

If we substitute these values into equation 1, we will get 27.18 Joules per Kelvin.