Question

Water from a tap emerges vertically downwards with initial velocity 6 ms–1. The cross-sectional area of the tap is



a. The flow is steady and pressure is constant throughout the stream of water. The distance h vertically below the tap, where the cross-sectional area of the stream becomesa, is (g = 10 ms–2).

Answer 1

Answer:

Apply eqn of continuity ie a1v1=a2v2

Here a1=a and a2=A

v1=6 and v2=√36+20h

6a=A✓36+20h

Squaring

36a^2=A^2(36+20h)

(36(a/A)^2 -36)/20=h